KE = 1/2*m*v^2
Q = KE, assuming complete conversion to thermal energy.
Thus
Q = 1/2*m*v^2
Data:
m:=1050 kg; v:=250/9 meters/sec;
Result:
Q = 405093 Joules
Convert to kilocalories:
Q = 96.755 kcalHow many kilocalories of heat are generated when the brakes are used to bring a 1050 kg car to rest from a spe?The kinetic energy of a moving body is 1/2mv^2. Initially, the car therefore has kinetic energy of 405kJ. Once the car is at rest, there is no more kinetic energy, all that energy has been dissipated through heat.
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