How many kilocalories of heat are generated when the brakes are used to bring a 1010 kg car to rest from a speed of 103 km/h?
___ kcal
I originally solved it to get 351698.2, but thats incorrect, so any help is appreciatedHow many kilocalories of heat are generated when the brakes are used?KE transferred = work done by brakes
103 km/h = 28.61 m/s
1/2mv^2 = 0.5 x 1010 x 28.61^2 = 413390.82 J
413390.82 J = 98736.70106 cal
98736.70106/1000 = 98.736 Kcal
Subscribe to:
Post Comments
(Atom)
No comments:
Post a Comment